Physical Pharmaceutics 2 - Unit 5


Syllabus

Drug stability: Reaction kinetics: zero, pseudo-zero, first & second order, units of basic rate constants, determination of reaction order. Physical and chemical factors influencing the chemical degradation of pharmaceutical product: temperature, solvent, ionic strength, dielectric constant, specific & general acid base catalysis, Simple numerical problems. Stabilization of medicinal agents against common reactions like hydrolysis & oxidation. Accelerated stability testing in expiration dating of pharmaceutical dosage forms. Photolytic degradation and its prevention



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PHYSICAL PHARMACEUTICS-2 UNIT 5TH

DRUG STABILITY


Most Important Question

Drug Stability
  • It is the ability of a drug to maintain its quality, potency and safety over time without degradation, when stored under specified conditions.

Reaction Kinetics

  • It includes the study of the speed or rate of chemical process that occurs during chemical reactions.

    A (Reactant) \rightarrow B (product)

  • Rate of reactions, is the speed at which chemical reactions take place depends on concentration and time.

    Rateofreactions=±dcdt=change in concentrationchange in timeRate of reactions = \pm \frac{dc}{dt} = \frac{\text{change in concentration}}{\text{change in time}}


ZERO ORDER REACTIONS

  • These are those reactions, in which rate of reaction is independent of the concentration of the reactant.

  • In this, reaction rate remains constant because of zero order reaction.

    • Let,

A \rightarrow B $$Rate = k[A]^x$$ At this, x=0x=0 so, Rate=kRate = k

  • Rate of reaction =dAdt= \frac{-dA}{dt}
  • So, dAdt=k\frac{-dA}{dt} = k
  • Where,

    dAdt=\frac{-dA}{dt} = change in concentration with respect to time

    k=k = specific rate constant for zero order.


Derivation :

  • The rate of zero order =dAdt=k= \frac{-dA}{dt} = k or

    dA=k×dt-dA = k \times dt

  • On integrating both sides,

    dA=kdt\int dA = k \int dt

    [A]A0At=k[t]0t-[A]_{A_0}^{A_t} = k[t]_0^t


Screenshot 2026-04-05 113912


[AtA0]=k(t0)-[A_t - A_0] = k(t - 0)

A0At=ktA_0 - A_t = kt

k=A0Attk = \frac{A_0 - A_t}{t}

Where
k=k = rate constant
A0=A_0 = starting concn of reactant at t=0t=0
At=A_t = concn of reaction (final) after time t=timet=time


Half Life : It is the time required to reduce half amount of Initial concentration of reactant.

Initial concn=A0conc^n = A_0
Final concn=A02conc^n = \frac{A_0}{2} at half time t1/2t_{1/2}

  • By putting these value in main equation -
    k=A0A0/2t1/2k = \frac{A_0 - A_0/2}{t_{1/2}}
    k(t1/2)=A02k(t_{1/2}) = \frac{A_0}{2}
    t1/2=A02kt_{1/2} = \frac{A_0}{2k}
  • Half life is directly proportional to the initial concn of reactant.

Shelf Life : It is the time required to reduces the reactant concentration up to 90% from the initial concentration.

  • Initial concn=A0conc^n = A_0
  • Final concn=A=0.9(A0)conc^n = A = 0.9(A_0)
  • Putting these value into main eq

    k=A0At=A00.9A0t0.9k = \frac{A_0 - A}{t} = \frac{A_0 - 0.9 A_0}{t_{0.9}}
    t0.9=0.1A0kt_{0.9} = \frac{0.1 A_0}{k}

  • Shelf life for zero order reactions


FIRST ORDER REACTIONS

  • It is, when rate of reaction depend on the concentration of reactant.

    A \rightarrow B (product)
    Rate=k[A]1Rate = k[A]^1
    Rate=d(A)dtRate = \frac{-d(A)}{dt}

  • Equate both

    k[A]=d(A)dtk[A] = \frac{-d(A)}{dt}

or kdt=d(A)[A]k \cdot dt = \frac{-d(A)}{[A]}


Integration on Both Sides

kdt=dAAk \int dt = -\int \frac{dA}{A}
k[t]0t=[logA]A0Atk[t]_0^t = -[\log A]_{A_0}^{A_t}
kt=[logAtlogA0]kt = -[\log A_t - \log A_0]
kt=[logAtA0]Orkt=2.303log10[A0At]kt = -\left[\log \frac{A_t}{A_0}\right] \quad \text{Or} \quad kt = 2.303 \log_{10} \left[\frac{A_0}{A_t}\right]
k=2.303tlog[A0At]k = \frac{2.303}{t} \log \left[\frac{A_0}{A_t}\right]

For half life

kt1/2=2.303log[A0A0/2]k \cdot t_{1/2} = 2.303 \log \left[\frac{A_0}{A_0/2}\right]
t1/2=2.303log(2)kt_{1/2} = \frac{2.303 \log(2)}{k}
t1/2=0.693kt_{1/2} = \frac{0.693}{k}

  • Hint: At=A0ektA_t = A_0 e^{-kt} in exponential form

    Screenshot 2026-04-05 114039

  • For shelf life (t_{0.9}$) $\rightarrow At=0.9A0A_t = 0.9 A_0
    t0.9=2.303klog[A00.9A0]t_{0.9} = \frac{2.303}{k} \log \left[\frac{A_0}{0.9 A_0}\right]
    t0.9=2.303klog[10/9]t_{0.9} = \frac{2.303}{k} \log [10/9]
    t0.9=2.303klog[1.11]t_{0.9} = \frac{2.303}{k} \log [1.11]
    t0.9=0.105kt_{0.9} = \frac{0.105}{k}


Accelerated Stability Testing

  • Stability of drug product is the ability of drugs to maintain its quality (retains its properties).

Expiry Date

  • It is the time period, at which drug is safe but after this time drug is not considered for use.

  • Now, expiration date of drug is selected on the basis of its shelf life and its accelerated stability testing.

Shelf Life

  • It is defined as the time required for concn of the reactant to reduce 90% of its Initial / original concn.
  • Is the period of time at which food/drug maintain its safety and quality.

Accelerated Stability Testing

  • In this test, the rate of decomposition of drug is accelerated or increases by providing high temp, high humidity & light conditions.
  • Because, high temperature increase instability or decomposition of drug products.
  • From this, we get idea regarding decomposition of drug when it stored for long period of time.

  • In this we rise the temp for storage.
  • 25°C product
  • 45°C product
  • 40°C
  • 60°C
  • Relative humidity also increases
  • It is based on Arrhenius equation. $$k = A e^{-E_a/RT}$$
  • According to Arrhenius, for every 10°C rise in temp, speed of reaction increases upto 2-3 times.
  • Product stored at diff-diff temperatures.

Screenshot 2026-04-05 114206

  • After all this, Calculate its shelf life which is safe for the use of the products.

Degradation : It is the process of decreasing the quality of products.

Factor Affecting

  • Temperature
  • Light
  • Moisture/humidity
  • Degradation depends on \rightarrow pH, solvent, excipients, buffer.

Photolytic Degradation :

  • It is the process of decreasing the quality of product through sunlight/light.
  • Photon + lytic \rightarrow light breakdown its prevent \rightarrow Chem dy

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Unit 5, Physical Pharmaceutics 2, B Pharmacy 4th Sem, Carewell Pharma
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